United States presidential election, 1824
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The presidential election of 1824 was a hard and rough election. Secretary of State, John Quincy Adams ran as did the hero of the Battle of New Orleans, Andrew Jackson. Other candidates were John C. Calhoun, Henry Clay, and William H. Crawford. Jackson was the most popular, but still there was a close election. Things changed when Calhoun withdrew from the race and Crawford fell ill.
No candidate won a majority of electoral votes, so the election was decided by the House of Representatives. Henry Clay knew that he could not possibly win the presidency and decided that he would cast his support to John Quincy Adams. Adams then won the vote in the House and defeated Andrew Jackson.
Election Results[1]
| Candidate | Popular Vote[2] | Electoral Vote | House Vote |
|---|---|---|---|
| John Quincy Adams | 113,142 | 84 | 13 |
| Andrew Jackson | 151,363 | 99 | 7 |
| William H. Crawford | 41,032 | 41 | 4 |
| Henry Clay | 47,545 | 37 | 0 |
| Unpledged/Others | 12,846 | 0 | 0 |
References
- ↑ Dave Leip's Atlas of U.S. Presidential Elections, 1824 Presidential Election Results
- ↑ Only 18 of the 24 states chose electors through popular vote.
- ↑ A Pictoral History of the U.S. Presidents, by Clare Gibson, Gramercy Books, 2001.
