Difference between revisions of "Gradient"
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Evidently by the Cauchy-Schwartz inequality, the directional derivative in the direction <math>u</math> is maximal in the direction of the gradient, and equal to <math>||\nabla f||</math> for <math>u</math> a unit vector in the direction of the gradient. | Evidently by the Cauchy-Schwartz inequality, the directional derivative in the direction <math>u</math> is maximal in the direction of the gradient, and equal to <math>||\nabla f||</math> for <math>u</math> a unit vector in the direction of the gradient. | ||
| + | |||
| + | ==Properties of the Gradient== | ||
| + | |||
| + | If <math>f</math> is a differentiable function with smooth level sets <math>f^{-1}(c)</math>, then the gradient vector field <math>\nabla f</math> is perpendicular to the level sets of <math>f</math>. For fix a level set <math>S = f^{-1}(c)</math>, and let <math>v</math> be a vector tangent to <math>S</math> at <math>p</math>. Then we can find a curve <math>\gamma(t)</math> on <math>S</math> with <math>\gamma'(0) = v</math>. Now | ||
| + | |||
| + | <math> | ||
| + | f\circ\gamma(t) = c | ||
| + | </math> | ||
| + | |||
| + | since <math>S</math> is a level set. Taking derivatives of both sides and applying the chain rule, we get that | ||
| + | |||
| + | <math> | ||
| + | \nabla f\cdot \gamma'(0) = \nabla f\cdot v = 0 | ||
| + | </math> | ||
| + | |||
| + | Thus, <math>\nabla f</math> is perpendicular to <math>v</math> at <math>p</math>, i.e., the gradient of <math>f</math> is perpendicular to the level sets of <math>f</math>. | ||
[[Category:mathematics]] | [[Category:mathematics]] | ||
Revision as of 15:34, July 2, 2008
In mathematics, the gradient of a real-valued differentiable function
at a point
is a vector in
which points in the direction in which
increases most rapidly at
. The magnitude of the gradient at
is equal to the maximum directional derivative of
at
.
More precisely, we define the gradient,
of
to be the vector-field:
If
is a unit vector in
, then, by the chain rule, the directional derivative of
in the direction of
is simply the dot product:
Evidently by the Cauchy-Schwartz inequality, the directional derivative in the direction
is maximal in the direction of the gradient, and equal to
for
a unit vector in the direction of the gradient.
Properties of the Gradient
If
is a differentiable function with smooth level sets
, then the gradient vector field
is perpendicular to the level sets of
. For fix a level set
, and let
be a vector tangent to
at
. Then we can find a curve
on
with
. Now
since
is a level set. Taking derivatives of both sides and applying the chain rule, we get that
Thus,
is perpendicular to
at
, i.e., the gradient of
is perpendicular to the level sets of
.