# Difference between revisions of "Exact differential equation"

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:<math>M(t,y) + N(t,y)y' = 0\,</math> or <math>M(t,y) dt + N(t,y) dy = 0\,</math> | :<math>M(t,y) + N(t,y)y' = 0\,</math> or <math>M(t,y) dt + N(t,y) dy = 0\,</math> | ||

− | + | Before we begin solving it, we must first check that the equation is exact. This means that: | |

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− | φ | + | <math>\frac{\partial M}{\partial y} = \frac{\partial N}{\partial t}</math> |

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+ | To find the solution of this equation, we assume that the solution is φ = constant. We can re-write a different form of this equation by substituting <math>\frac{\partial \phi}{\partial t} = M</math> and <math>\frac{\partial \phi}{\partial y} = N</math>. This yields <math>(\frac{\partial \phi}{\partial t}) dt + (\frac{\partial \phi}{\partial y}) dy = 0</math>, which makes sense. | ||

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+ | to find φ, we integrate M with respect to t and N with respect to y. This will give us two different equations. To find φ , we | ||

Go through the example to find φ by integrating, then check that | Go through the example to find φ by integrating, then check that | ||

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and that any function φ = some constant, when turned into the corresponding dy/dt, satisfies the original equation. Be sure to emphasize that one must check first that | and that any function φ = some constant, when turned into the corresponding dy/dt, satisfies the original equation. Be sure to emphasize that one must check first that | ||

:<math>\frac{\partial M}{\partial y} = \frac{\partial N}{\partial t}</math> | :<math>\frac{\partial M}{\partial y} = \frac{\partial N}{\partial t}</math> | ||

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To find <math>y</math>, first set <math>M = \frac{\partial \phi}{\partial t}</math> and <math>N = \frac{\partial \phi}{\partial y}</math>. Then manipulate to get <math>M \partial t = \partial \phi</math> and <math>N \partial y = \partial \phi</math>. Integrate both sides, compare the results for <math>\phi</math>, and combine the terms into one equation (for terms that show up in both expressions, only write once in the combined expression.) To solve the expression for <math>y</math>, plug into the quadratic formula. | To find <math>y</math>, first set <math>M = \frac{\partial \phi}{\partial t}</math> and <math>N = \frac{\partial \phi}{\partial y}</math>. Then manipulate to get <math>M \partial t = \partial \phi</math> and <math>N \partial y = \partial \phi</math>. Integrate both sides, compare the results for <math>\phi</math>, and combine the terms into one equation (for terms that show up in both expressions, only write once in the combined expression.) To solve the expression for <math>y</math>, plug into the quadratic formula. |

## Revision as of 13:46, 2 August 2010

An **exact differential equation** is a differential equation that can be solved in the following manner.

Suppose you are given an equation of the form:

- or

Before we begin solving it, we must first check that the equation is exact. This means that:

To find the solution of this equation, we assume that the solution is φ = constant. We can re-write a different form of this equation by substituting and . This yields , which makes sense.

to find φ, we integrate M with respect to t and N with respect to y. This will give us two different equations. To find φ , we

Go through the example to find φ by integrating, then check that

and

and that any function φ = some constant, when turned into the corresponding dy/dt, satisfies the original equation. Be sure to emphasize that one must check first that

To find , first set and . Then manipulate to get and . Integrate both sides, compare the results for , and combine the terms into one equation (for terms that show up in both expressions, only write once in the combined expression.) To solve the expression for , plug into the quadratic formula.