Difference between revisions of "Natural logarithm"

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The natural logarithm has some interesting properties that follow from the multiplicative properties of <math>e^x</math>.  The natural logarithm is also particularly useful in calculating [[interest]].
 
The natural logarithm has some interesting properties that follow from the multiplicative properties of <math>e^x</math>.  The natural logarithm is also particularly useful in calculating [[interest]].
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== Properties of the Logarithm ==
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*<math>\ln(ab) = \ln(a)+\ln(b)</math> for all positive reals <math>a,b</math>.
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Proof: If <math>a,b > 0</math>, we can write <math>a = e^x</math> and <math>b= e^y</math>. It follows that <math>\ln(ab) = \ln(e^x e^y) = \ln(e^{x+y})</math>. By definition, <math>\ln(e^{x+y}) = x+y = \ln(e^x)+\ln(e^y)</math>. This last expression, of course, is <math>\ln(a)+\ln(b)</math>.
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*<math>\ln(x^p) = p\ln(x)</math>
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Proof: If <math>p</math> is a positive integer, this just follows from repeated application of the above-mentioned additive property of the logarithm. For <math>p = \frac{1}{n}</math>, note that the statement follows by observing that <math>\ln(x) = \ln((x^{1/n})^n) = n\ln(x^{1/n}</math>. Thus, <math>p\ln(x) = \ln(x^p)</math> for all rational numbers <math>p</math>. The statement must therefore hold for all reals <math>p</math> by continuity.
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*<math>\ln(1) = 0</math>
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Proof: <math>\ln(1) = \ln(1\cdot 1) = \ln(1)+\ln(1)</math>, whence we must have <math>\ln(1)=0</math>.
 
[[Category:Mathematics]]
 
[[Category:Mathematics]]

Revision as of 00:55, May 26, 2009

red: natural logarithm

The natural logarithm, is the inverse of the function . In other words, if , we define .

The natural logarithm has some interesting properties that follow from the multiplicative properties of . The natural logarithm is also particularly useful in calculating interest.

Properties of the Logarithm

  • for all positive reals .

Proof: If , we can write and . It follows that . By definition, . This last expression, of course, is .

Proof: If is a positive integer, this just follows from repeated application of the above-mentioned additive property of the logarithm. For , note that the statement follows by observing that . Thus, for all rational numbers . The statement must therefore hold for all reals by continuity.

Proof: , whence we must have .