Difference between revisions of "Exact differential equation"
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Suppose you are given an equation of the form: | Suppose you are given an equation of the form: | ||
| − | :<math>M(t,y) + N(t,y)y' = 0\,</math> or <math>M(t,y) dt + N(t,y) dy = 0\,</math> (we will call this equation 1) | + | :<math>M(t,y) + N(t,y)y' = 0\,</math> or <math>M(t,y) dt + N(t,y) dy = 0\,</math> |
| + | (we will call this equation 1) | ||
Revision as of 18:56, August 2, 2010
An exact differential equation is a differential equation that can be solved in the following manner.
Suppose you are given an equation of the form:
or 
(we will call this equation 1)
Before we begin solving it, we must first check that the equation is exact. This means that:
To find the solution of this equation, we assume that the solution is φ = constant. We assume that
and
. (If we substitute M and N back into (1), it yields
, which makes sense.)
To find
, manipulate the substitutions of M and N to get
and
. Integrate both sides. To get the main function φ write the sum of each term found in each equation. For terms that appear in both equations, only write them once.
To solve the expression for
, use the quadratic formula.