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Maths formatting
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In [[physics]], work refers to the product of [[force]] and [[distance]] vectors
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In [[physics]], '''work''' refers to the [[dot product]] of [[force]] and [[distance]] vectors
<ref>Serway and Beichner, ''Physics for Scientists and Engineers'', Fifth Edition</ref>.
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.<ref>Serway and Beichner, ''Physics for Scientists and Engineers'', Fifth Edition</ref>
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''W'' = F · d
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<math>W = \vec{F} \cdot \vec{d}</math>
    
Or:
 
Or:
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''W'' = F d Cosθ
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<math>W = Fd \cos{\theta}</math>
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Where θ is the angle that separates the vectors.
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Where θ is the angle that separates the vectors. The second form of the equation is the expanded form of the "dot product" in the first equation. In physics, the dot product <math>\vec{a} \cdot \vec{b}</math> (read "a dot b") can be rewritten as <math>|\vec{a}| |\vec{b}| \cos{\theta}</math>.  
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Work is a transfer of [[energy]]; if ''W'' is positive, there is a transfer of energy ''to'' the system, and if ''W'' is negative there is a transfer of energy ''from'' the system.
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When the force is not constant, the correct expression uses [[integration]]:
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Its units are that of force multiplied by distance, in SI this is [[newton (unit)|Newton]] · [[Meter]], or [[Joule]]
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<math>\int \vec{F} \cdot \mathrm{d}\vec{s}</math>
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Work is a transfer of [[energy]]; if <math>W</math> is positive, there is a transfer of energy ''to'' the system, and if <math>W</math> is negative there is a transfer of energy ''from'' the system.
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Its units are that of force multiplied by distance, in SI this is [[newton (unit)|Newton]] · [[Meter]], or [[Joule]]. The aberrant unit kWh (kilowatt-hour) is sometimes used; this unit is the product of kilowatt, or 1,000 Watts (Joules per second), and hour, or 3,600 seconds.
    
==References==
 
==References==
 
<references/>
 
<references/>
[[category:physics]]
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[[Category:Physics]]
 
[[Category:Mechanics]]
 
[[Category:Mechanics]]

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