Block, SkipCaptcha, Upload, Automoderated users, edit, rollback
14,697
edits
Changes
Pythagorean theorem (view source)
Revision as of 09:23, February 15, 2021
, 09:23, February 15, 2021→Reasoning: reframed reasoning steps
2. And since ''l''<sub>1</sub> and ''l''<sub>2</sub> are whole numbers, that which results when they are multiplied by themselves, namely ''l''<sub>1</sub><sup>2</sup> and ''l''<sub>2</sub><sup>2</sup>, certainly are as well.
2. And since ''l''<sub>1</sub> and ''l''<sub>2</sub> are whole numbers, that which results when they are multiplied by themselves, namely ''l''<sub>1</sub><sup>2</sup> and ''l''<sub>2</sub><sup>2</sup>, certainly are as well.
3. So let's relabel ''l''<sub>1</sub><sup>2</sup> and ''l''<sub>2</sub><sup>2</sup>, ''o''<sub>1</sub> and ''o''<sub>2</sub>, to show they are natural numbers like the ''n'''s.
3. So let's assign ''o''<sub>1</sub> as being equal to ''l''<sub>1</sub><sup>2</sup> and ''o''<sub>2</sub> as being equal to ''l''<sub>2</sub><sup>2</sup>, ''o''<sub>1</sub> and ''o''<sub>2</sub>, to limit them to showing they are natural numbers like the ''n'''s in the "simple assumption":
:(''o''<sub>1</sub> / ''h'') + (''o''<sub>2</sub> / ''h'') = ''h''.
===Conceptualization (cont'd)===
===Conceptualization (cont'd)===