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*(''x''<sup>0</sup>) · (''x''<sup>n</sup>) = ''x''<sup>0 + n</sup> = ''x''<sup>n</sup>
*(''x''<sup>0</sup>) · (''x''<sup>n</sup>) = ''x''<sup>0 + n</sup> = ''x''<sup>n</sup>
Dividing both sides by ''x''<sup>n</sup> we get
Dividing both sides by ''x''<sup>n</sup> we get
*(''x''<sup>0</sup) = 1
*(''x''<sup>0</sup>) = 1
A negative exponent produces the [[reciprocal]] of the corresponding positive exponent:
A negative exponent produces the [[reciprocal]] of the corresponding positive exponent: