Siteadmin, Bureaucrats, Check users, nsAm_Govt_101RO, nsAm_Govt_101RW, nsAm_Govt_101_ta, nsJudgesRO, nsJudgesRW, nsJudges_talkRO, nsJudges_talkRW, nsTeam2RO, nsTeam2RW, nsTeam2_talkRO, nsTeam2_talkRW, oversight, Administrators
125,789
edits
Changes
Jump to navigation
Jump to search
Line 47:
Line 47: − + − +
no edit summary
:<math> = \int_0^\frac{\pi}{4}\sin{x}\,(\frac{\sin{x}}{\cos^3{x}})\,dx</math>
:<math> = \int_0^\frac{\pi}{4}\sin{x}\,(\frac{\sin{x}}{\cos^3{x}})\,dx</math>
:<math> = \frac{\sin{x}}{2\cos^2{x}} - \int_0^\frac{\pi}{4}\frac{sec{x}}{2},\,dx</math>
:<math> = \frac{\sin{x}}{2\cos^2{x}} - \int_0^\frac{\pi}{4}\frac{\sec{x}}{2},\,dx</math>
Recall that:
Recall that:
:\int{sec{x},\,dx = tan{x}</math>
:<math>\int{\sec{x},\,dx = \tan{x}</math>
and the solution becomes obvious.
and the solution becomes obvious.
[[category:mathematics]]
[[category:mathematics]]
[[category:calculus]]
[[category:calculus]]