Difference between revisions of "Power rule"

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WE ARE THE TK CONSERVAPEDIA DESTRUCTION ARMY
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The '''power rule''' allows one to calculate the derivative of a power of a function in terms of the derivative of the function itself.  The power rule states that
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Welcome to the guild TK
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<math> \frac{d}{dx} (x^n) = nx^{n-1} </math>
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for all integers <math> n </math>.  This rule is useful when combined with the [[chain rule]].  As an example we can compute the derivative of <math> f(x) = (\sin(x))^n</math> as
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<math> f'(x) = \frac{d}{dx} (\sin(x))^n = n(\sin(x))^{n-1}\cos(x) </math>
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==Proof==
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The power rule is simple and elegant to prove with the definition of a derivative:
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:<math>f'(x) = \lim_{h\rarr0} \frac{f(x+h)-f(x)}{h}. </math>
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Substituting <math> f(x) = x^n </math> gives
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:<math>f'(x) = \lim_{h\rarr0} \frac{(x+h)^n-x^n}{h}.</math>
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The two polynomials in the numerator can be factored out. It is left as a series, since n can be any integer.
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:<math>f'(x) = \lim_{h\rarr0} \frac{((x+h) - x)( (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2 + \dots + (x+h)x^{n-2} + x^{n-1})}{h}. </math>
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Then if the first factor is eliminated:
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:<math>f'(x) = \lim_{h\rarr0} \frac{(h)( (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2\dots + (x+h)x^{n-2} + x^{n-1})}{h}. </math>
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Now, the "h" can be eliminated. This is important, since the denominator cannot go to zero':
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:<math>f'(x) = \lim_{h\rarr0} (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2\dots + (x+h)x^{n-2} + x^{n-1}. </math>
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With no "h" in the denominator, the limit can be evaluated by letting h=0.
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:<math>f'(x) = (x+0)^{n-1} + (x+0)^{n-2}x + (x+0)^{n-3}x^2\dots + (x+0)x^{n-2} + x^{n-1}. </math>:
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:<math>f'(x) = x^{n-1} + x^{n-1} + x^{n-1}\dots + x^{n-1} + x^{n-1}. </math>
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We see that there are ''n'' terms,  so:
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:<math>f'(x) = nx^{n-1}. </math>
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QED
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==Rules for finding derivatives==
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*Power rule
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*[[Constant-multiple rule]]
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*[[sum rule]]
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*[[Chain rule]]
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*[[Product rule]]
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*[[Quotient rule]]
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[[Category:Mathematics]]
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[[Category:Calculus]]
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[[Category:Differentiation]]

Latest revision as of 14:01, August 29, 2017

The power rule allows one to calculate the derivative of a power of a function in terms of the derivative of the function itself. The power rule states that

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{d}{dx} (x^n) = nx^{n-1} }

for all integers Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n } . This rule is useful when combined with the chain rule. As an example we can compute the derivative of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x) = (\sin(x))^n} as

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \frac{d}{dx} (\sin(x))^n = n(\sin(x))^{n-1}\cos(x) }

Proof

The power rule is simple and elegant to prove with the definition of a derivative:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \lim_{h\rarr0} \frac{f(x+h)-f(x)}{h}. }

Substituting Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(x) = x^n } gives

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \lim_{h\rarr0} \frac{(x+h)^n-x^n}{h}.}

The two polynomials in the numerator can be factored out. It is left as a series, since n can be any integer.

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \lim_{h\rarr0} \frac{((x+h) - x)( (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2 + \dots + (x+h)x^{n-2} + x^{n-1})}{h}. }

Then if the first factor is eliminated:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \lim_{h\rarr0} \frac{(h)( (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2\dots + (x+h)x^{n-2} + x^{n-1})}{h}. }

Now, the "h" can be eliminated. This is important, since the denominator cannot go to zero':

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = \lim_{h\rarr0} (x+h)^{n-1} + (x+h)^{n-2}x + (x+h)^{n-3}x^2\dots + (x+h)x^{n-2} + x^{n-1}. }

With no "h" in the denominator, the limit can be evaluated by letting h=0.

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = (x+0)^{n-1} + (x+0)^{n-2}x + (x+0)^{n-3}x^2\dots + (x+0)x^{n-2} + x^{n-1}. } :
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = x^{n-1} + x^{n-1} + x^{n-1}\dots + x^{n-1} + x^{n-1}. }

We see that there are n terms, so:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f'(x) = nx^{n-1}. }

QED

Rules for finding derivatives