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Talk:Pi (view source)

Revision as of 03:25, August 1, 2021

718 bytes added ,  03:25, August 1, 2021
→‎Pi contains pi: Infinity has no such limit. Embrace its vastness and make it work for you. It can be enormously beneficial at a personal level for someone's outlook, and not something to be resisted through infinity denial
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::::#''a sequence contains a countably infinite sub-sequence with a certain property''
 
::::#''a sequence contains a countably infinite sub-sequence with a certain property''
 
:::The first statement does not imply the second one. --[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 17:44, July 31, 2021 (EDT)
 
:::The first statement does not imply the second one. --[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 17:44, July 31, 2021 (EDT)
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::::Your proposed proof has the fallacy of assuming a termination on an infinite sequence (and thus periodicity).  There is no such termination.
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::::Your criticism of my proof by induction is also flawed.  Do you really think that your examples for n and n+1 will stop existing in the infinite sequence of digits for [[pi]], at some large n?  Your position essentially denies the extent of [[infinity]].
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::::[[Infinity]] has no such limit.  Embrace its vastness and make it work for you.  It can be enormously beneficial at a personal level for someone's outlook, and not something to be resisted through [[infinity denial]].--[[User:Aschlafly|Andy Schlafly]] ([[User talk:Aschlafly|talk]]) 23:25, July 31, 2021 (EDT)
Aschlafly
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