Alternatively, <math>a_n(x) y^n + a_{n-1}(x) y^{n-1} + a_1(x) y + a_0(x) = 0</math>, where <math> a_n(x), a_{n-1}(x), \cdots, a_1(x), a_0(x)</math> are themselves polynomials in x. | Alternatively, <math>a_n(x) y^n + a_{n-1}(x) y^{n-1} + a_1(x) y + a_0(x) = 0</math>, where <math> a_n(x), a_{n-1}(x), \cdots, a_1(x), a_0(x)</math> are themselves polynomials in x. |