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m
Maths formatting
Line 27: Line 27:  
:<math>\mathbf{L_i}=\mathbf{L_f}</math>  
 
:<math>\mathbf{L_i}=\mathbf{L_f}</math>  
   −
:<math>\mathbf{m}\times{v}\times{l}= \mathbf{I}\times{\omega}</math>
+
:<math>mvl= I \omega</math>
    
Thus
 
Thus
Line 88: Line 88:  
and thus the solution is:
 
and thus the solution is:
   −
:<math>\mathbf{cos\theta} = 1 - \frac{{6m^2}{h}}{l\times{(2m+M)(3m+M)}}</math>
+
:<math>cos\theta = 1 - \frac{{6m^2}{h}}{l(2m+M)(3m+M)}</math>
    
or
 
or
   −
:<math>\mathbf{\theta} = arccos(1 - \frac{{6m^2}{h}}{l\times{(2m+M)(3m+M)}})</math>
+
:<math>\theta = \arccos{\bigg( 1 - \frac{{6m^2}{h}}{l(2m+M)(3m+M)} \bigg)}</math>
    
[[Category:Physics]]
 
[[Category:Physics]]
 
[[Category:Mechanics]]
 
[[Category:Mechanics]]

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