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| − | As part of the Betha [[Chemistry]] Tutorial created by the [[Ohio State University]]'s Department of Chemistry, the following explanation was given:
| + | The '''trajectory''' of an object is the path it takes through space. It is often described by the [[position]] of an object as a function of time. An example is that of a cannon ball, but it applies to any path such as the [[orbit]] of a [[planet]] or a rocket in space. In [[classical mechanics]], the trajectory of a particle with mass m is described by [[Newton's Laws of Motion|Newton's second law]], |
| − | {{quotebox|The x, y and z coordinates of a particle as a function of time are known as the trajectory or orbit of a particle. The laws of classical physics predict the trajectory of a particle for all times once the position and velocity are known at some initial time. For example, if the position and velocity of a cannonball are known at the instant it leaves a cannon, the classical mechanics can predict the path taken by the cannonball at later times and where it will land.<ref>[http://www.chemistry.ohio-state.edu/betha/qm/1bfrb.html "An Introduction to Quantum Mechanics" at Ohio State University]</ref>}} | + | |
| | + | <math> |
| | + | m \frac{d^2\vec{x}}{dt^2} = \vec{F} |
| | + | </math> |
| | + | |
| | + | where <math>\vec{F}</math> is the net [[force]] that acts on the particle. |
| | + | |
| | + | ==Projectile motion== |
| | + | |
| | + | A useful example of trajectories is that of projectile motion, such as the motion of a cannon ball. The simplest case is that of where drag is ignored and the force of [[gravity]] on the projectile is taken to be constant. In this case, an exact solution for the trajectory may be found using the [[SUVAT equations]]. As the [[acceleration]] of the particle in the x and y directions are independent, the motion in each dimension can be considered separately. For a body with initial speed, u, fired at an angle θ above the horizontal, the x an y components of the body's [[velocity]] can be split into components: <math>u_x = v \cos{\theta}</math> and <math>u_y = u \sin{\theta}</math>. The x and y positions of the particle can be expressed as: |
| | + | |
| | + | <math> |
| | + | x(t) = u_x t = u \cos{\theta} t |
| | + | </math> |
| | + | |
| | + | <math> |
| | + | y(t) = u_y t - \frac{1}{2}gt^2 = u \sin{\theta} t - \frac{1}{2}gt^2 |
| | + | </math> |
| | + | |
| | + | These can be rearranged so that the trajectory followed is: |
| | + | |
| | + | <math> |
| | + | y(x) = x \tan{\theta} - \frac{g}{2u^2 \cos^2{\theta}}x^2 |
| | + | </math> |
| | + | |
| | + | Hence the path followed by a body such as cannon ball is roughly [[quadratic equation|parabolic]]. |
| | + | |
| | + | ===Range and Maximum Height=== |
| | + | |
| | + | For the case of uniform gravity and no air resistance, the range of a body can be found by solving y = 0: |
| | + | |
| | + | <math> |
| | + | x_{max} = \frac{2u^2 \cos^2{\theta} \tan{\theta}}{g} = \frac{u^2 \sin{2\theta}}{g} |
| | + | </math> |
| | + | |
| | + | The maximum height can be found as: |
| | + | |
| | + | <math> |
| | + | y_{max} = \frac{u^2 \sin^2{\theta}}{2g} |
| | + | </math> |
| | + | |
| | + | ==See Also== |
| | + | * [[Classical mechanics]] |
| | + | * [[SUVAT equations]] |
| | + | |
| | + | ==External Links== |
| | + | [http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html Trajectory at Hyperphysics] |
| | | | |
| − | ==References==
| |
| − | <references/>
| |
| | [[Category:Physics]] | | [[Category:Physics]] |
| | + | [[Category:Mechanics]] |