4. If the sum of square of the lengths happened to be a whole number divisible by some hypoteneuse, it must be divided by an odd prime hypoteneuse. Odd numbers take the form of 2n + 1, which when squared gives 4n<sup>2</sup> + 4n + 1, which also must be an odd number. Two odd numbers summed always gives an even number, which would result in the sum of square of the lengths not being fully divisible by any odd prime hypoteneuse. | 4. If the sum of square of the lengths happened to be a whole number divisible by some hypoteneuse, it must be divided by an odd prime hypoteneuse. Odd numbers take the form of 2n + 1, which when squared gives 4n<sup>2</sup> + 4n + 1, which also must be an odd number. Two odd numbers summed always gives an even number, which would result in the sum of square of the lengths not being fully divisible by any odd prime hypoteneuse. |