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Line 45:
Line 45: − + − +
corrected
:<math>\int_0^\frac{\pi}{4}(\sec{x}\,\tan{x})^2\,dx</math>
:<math>\int_0^\frac{\pi}{4}(\sec{x}\,\tan{x})^2\,dx</math>
:<math> = \int_0^\frac{\pi}{4}\sin{x}\,(\frac{\sin{x}}{\cos^3{x}})\,dx</math>
:<math> = \int_0^\frac{\pi}{4}\sin{x}\,(\frac{\sin{x}}{\cos^4{x}})\,dx</math>
:<math> = \frac{\sin{x}}{2\cos^2{x}} - \int_0^\frac{\pi}{4}\frac{\sec{x}}{2},\,dx</math>
:<math> = \frac{\sin{x}}{3\cos^3{x}} - \int_0^\frac{\pi}{4}\frac{\sec^2{x}}{3},\,dx</math>
Recall that:
Recall that: