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| | ===Algebraic Substitution=== | | ===Algebraic Substitution=== |
| | + | '''Integration by Algebraic Substitution''' is a [[Techniques of integration|technique]] to facilitate the integration of a rational expression by substituting a more complicated expression with a variable. |
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| | + | Given an integral |
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| | + | :<big><math>\int\frac{2x}{x^2+3}dx</math></big> |
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| | + | We can substitute the term :<big><math>x^2+3</math></big> with a u. Giving us |
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| | + | :<big><math>u=x^2+3</math></big> |
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| | + | We then take the derivative of u with respect to x, |
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| | + | :<big><math>\frac{du}{dx}x^2+3=2x</math></big> |
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| | + | We then set the terms equal to du, |
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| | + | :<big><math>du=2xdx</math></big> |
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| | + | Now we are ready to rewrite the integral, |
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| | + | :<big><math>\int\frac{2x}{x^2+3}dx=\int\frac{1}{u}du</math></big> |
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| | + | We can rewrite the intergal this way due to the subsitution of the x terms with the u terms. |
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| | + | Now we can solve the intergral in terms of u. |
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| | + | :<big><math>\int\frac{1}{u}du=ln|u|+c</math></big> |
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| | + | Now we replace u with the term :<big><math>x^2+3</math></big> to get, |
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| | + | :<big><math>ln|x^2+3|+c</math></big> |
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| | + | We can check this by taking the derivative of :<big><math>ln|x^2+3|</math></big>, |
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| | + | :<big><math>\frac{d}{dx}ln|x^2+3|=(\frac{1}{x^2+3})(2x)=\frac{2x}{x^2+3}</math></big> |
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| | ===Trigonometric Substitution=== | | ===Trigonometric Substitution=== |