Because <math>x^2\ge0</math> for every <math>x</math>, <math>(-x)(-x)=x^2\ge0</math> for every <math>x</math>. The number for every <math>-1<0</math> is negative, therefore the [[polynomial]] <math>x^2 = -1</math> has no real solutions, and the ''imaginary'' solution <math>i</math>, where <math>i^2=-1</math>, is called an ''imaginary'' number because no such number solves this equation and does not exist, as just shown. | Because <math>x^2\ge0</math> for every <math>x</math>, <math>(-x)(-x)=x^2\ge0</math> for every <math>x</math>. The number for every <math>-1<0</math> is negative, therefore the [[polynomial]] <math>x^2 = -1</math> has no real solutions, and the ''imaginary'' solution <math>i</math>, where <math>i^2=-1</math>, is called an ''imaginary'' number because no such number solves this equation and does not exist, as just shown. |