Changes

Jump to navigation Jump to search
almost done, last proof not quite there
Line 62: Line 62:  
11. (Challenging, with extra credit) Prove mathematically that MC>MR for all Q>0 in the honors discussion above. (Hint: define MC in terms of the change in AVC, and then regroup the terms and draw conclusions about them to show MC>MR).
 
11. (Challenging, with extra credit) Prove mathematically that MC>MR for all Q>0 in the honors discussion above. (Hint: define MC in terms of the change in AVC, and then regroup the terms and draw conclusions about them to show MC>MR).
   −
:
+
:No student attempted this!  Perhaps I made it too scary.  Using the hint, I define MC in terms of AVC: MC for the "Q+1" unit is: MC(Q+1)=TC(Q+1)-TC(Q).  Next I can write TC in terms of AVC:  TC=AVC*Q.  Thus MC(Q+1)=AVC(Q+1)*(Q+1) - AVC(Q)*Q.  Thus MC(Q+1)=AVC(Q+1)*Q + AVC(Q+1) - AVC(Q)*Q.  Now regroup as the hint suggests: MC(Q+1)=Q*(AVC(Q+1)-AVC(Q)) + AVC(Q+1) <in progress>
−
 
  −
:
 
Siteadmin, Bureaucrats, Check users, nsAm_Govt_101RO, nsAm_Govt_101RW, nsAm_Govt_101_ta, nsJudgesRO, nsJudgesRW, nsJudges_talkRO, nsJudges_talkRW, nsTeam2RO, nsTeam2RW, nsTeam2_talkRO, nsTeam2_talkRW, oversight, Administrators
125,797

edits

Navigation menu