::::*''If the characteristic polynom splits into linear factors, then the determinant equals the product of the eigenvalues to the power of their algebraic multiplicity''
::::*''If the characteristic polynom splits into linear factors, then the determinant equals the product of the eigenvalues to the power of their algebraic multiplicity''
::::Thanks, [[User:FrankC|FrankC aka ComedyFan]] 09:48, 4 May 2010 (EDT)
::::Thanks, [[User:FrankC|FrankC aka ComedyFan]] 09:48, 4 May 2010 (EDT)
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:::::Well, I [[determinant|changed]] it myself... [[User:FrankC|FrankC aka ComedyFan]] 08:50, 5 May 2010 (EDT)
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:::::Well, I [[determinant|changed]] it myself (see [[talk:determinant]] for details) ... [[User:FrankC|FrankC aka ComedyFan]] 08:50, 5 May 2010 (EDT)