Difference between revisions of "Gamma function"
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:<math>= \left[t^{z-1}(-e^{-t}) \right]_0^{\infty}- \int_{0}^{\infty}(z-1)t^{(z-2)}(-e^{-t})dt</math> | :<math>= \left[t^{z-1}(-e^{-t}) \right]_0^{\infty}- \int_{0}^{\infty}(z-1)t^{(z-2)}(-e^{-t})dt</math> | ||
:<math>=(z-1) \int_{0}^{\infty}t^{(z-1)-1}e^{-t}dt</math> | :<math>=(z-1) \int_{0}^{\infty}t^{(z-1)-1}e^{-t}dt</math> | ||
| − | :<math>=(z-1) \Gamma(z-1)</math> | + | :<math>=(z-1) \Gamma(z-1).</math> |
Thus, | Thus, | ||
:<math> \Gamma (z) = (z-1) \Gamma(z-1)</math> | :<math> \Gamma (z) = (z-1) \Gamma(z-1)</math> | ||
| Line 15: | Line 15: | ||
:<math> \Gamma(n) = (n-1)!. </math> | :<math> \Gamma(n) = (n-1)!. </math> | ||
| + | |||
| + | [[category:mathematics]] | ||
Revision as of 20:31, June 5, 2010
The Gamma funciton is defined as
Using integration by parts,
Thus,
Using this, and the the fact that , then we can get the factorial. For a positive integer,