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Revision as of 20:20, July 25, 2021
1 byte added
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20:20, July 25, 2021
→Proof that π does not contain π:
Line 27:
Line 27:
x<sub>0</sub>x<sub>1</sub>x<sub>2</sub>x<sub>3</sub>...x<sub>n-1</sub> / (10<sup>n-1</sup> -1)
x<sub>0</sub>x<sub>1</sub>x<sub>2</sub>x<sub>3</sub>...x<sub>n-1</sub> / (10<sup>n-1</sup> -1)
−
5) It is well
know
that π is not a rational number, so we have a contradiction. Ergo, π cannot contain itself.
+
5) It is well
known
that π is not a rational number, so we have a contradiction. Ergo, π cannot contain itself.
--[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 13:18, July 25, 2021 (EDT)
--[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 13:18, July 25, 2021 (EDT)
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