Changes

more
Line 36: Line 36:     
Calculating the moment of inertia ''I'' now becomes necessary for a rod of length ''l'' and mass ''M'', with a small block of mass ''m'' at its end.
 
Calculating the moment of inertia ''I'' now becomes necessary for a rod of length ''l'' and mass ''M'', with a small block of mass ''m'' at its end.
 +
 +
An ordinary rod of length ''l'' has the following moment of inertia relative to an origin at one end:
 +
 +
:<math>\mathbf{I}= \frac{M}{3}\times\l^2</math>
       
[[category:physics]]
 
[[category:physics]]
Anthony, Irenaeus, Siteadmin, apieditor, Bureaucrats, Check users, nsAm_Govt_101RO, nsAm_Govt_101RW, nsAm_Govt_101_ta, nsJudgesRO, nsJudgesRW, nsJudges_talkRO, nsJudges_talkRW, nsTeam2RO, nsTeam2RW, nsTeam2_talkRO, nsTeam2_talkRW, oversight, Administrators
126,358

edits