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::Oh, and while we're at it, here's some (still voluntary response-based!) [http://en.wikipedia.org/wiki/Category:Moderate_Wikipedians data] for the third category. [[User:John Brown|John Brown]] 22:07, 15 March 2007 (EDT)
 
::Oh, and while we're at it, here's some (still voluntary response-based!) [http://en.wikipedia.org/wiki/Category:Moderate_Wikipedians data] for the third category. [[User:John Brown|John Brown]] 22:07, 15 March 2007 (EDT)
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A bit more can be said when there are moderates. If we accept that WL/AL = ((WL/(WC+WL+WU))/((AL/(AC+AL+AU)) = (2 + 1 + AU/AL)/(1/3 + 1 + WU/WL) = (3 + AU/AL)/(4/3 + WU/WL) = 6, the the lower bound on AU/AL is when WU = 0, so (3 + AU/AL)/(4/3) = 6, so 3 + AU/AL = 8, so AU/AL = 5. The data presented support the conclusion that there are at least 5 times as many undecided Americans as liberal Americans. [[User:Hdelbrook|Hdelbrook]] 22:21, 15 March 2007 (EDT)
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