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Talk:Axiom of Choice (view source)
Revision as of 23:44, November 27, 2008
, 23:44, November 27, 2008→My edits: Oh, and BRichtigen, too!
{{cquote|'''Abstract.''' In this paper we show that the Axioms of Zermelo-Fraenkel set theory together with the Hahn-Banach theorem imply the existence of a non-Lebesgue measurable set. Our construction does not make any use of the Axiom of Choice.}}
{{cquote|'''Abstract.''' In this paper we show that the Axioms of Zermelo-Fraenkel set theory together with the Hahn-Banach theorem imply the existence of a non-Lebesgue measurable set. Our construction does not make any use of the Axiom of Choice.}}
:So the other direction of the claim is apparently wrong, and AndyJM was right to remove it. He was blocked for "removing information from articles" by the same user who also re-inserted the apparently wrong claim. This is exactly why I oppose this "Block first" approach: How can we improve this encyclopedia when we can get blocked and banned by whoever ''thinks'' we're wrong? I suggest an unblock. --[[User:AlanS|AlanS]] 18:38, 27 November 2008 (EST)
:So the other direction of the claim is apparently wrong, and AndyJM was right to remove it. He was blocked for "removing information from articles" by the same user who also re-inserted the apparently wrong claim. This is exactly why I oppose this "Block first" approach: How can we improve this encyclopedia when we can get blocked and banned by whoever ''thinks'' we're wrong? I suggest an unblock. --[[User:AlanS|AlanS]] 18:38, 27 November 2008 (EST)
:Oh, and it'd be ''awesome'' if anybody could unblock BRichtigen, who was blocked by the same user for questioning the assertion that the two concepts are equivalent. --[[User:AlanS|AlanS]] 18:44, 27 November 2008 (EST)