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Talk:Probability density function (view source)
Revision as of 05:06, August 31, 2009
, 05:06, August 31, 2009redundant definition?
Obviously, a probability density function isn't necessarily continuous, take, e.g., the uniform distribution on [0,1] which has a rectangular function as pdf. I changed this in the article.
Obviously, a probability density function isn't necessarily continuous, take, e.g., the uniform distribution on [0,1] which has a rectangular function as pdf. I changed this in the article.
--[[User:BRichtigen|BRichtigen]] 08:01, 6 December 2008 (EST)
--[[User:BRichtigen|BRichtigen]] 08:01, 6 December 2008 (EST)
== Definition? ==
Maybe I'm missing something obvious here, but doesn't criterion (3) follow from criterion (1)? If that's the case it ought to be stated as a theorem and not part of the definition. (Of course, the reverse implication doesn't hold without a continuity assumption, so these aren't equivalent statements.) --[[User:MarkGall|MarkGall]] 01:06, 31 August 2009 (EDT)