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2 bytes added ,  01:24, February 12, 2010
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So, if a vector field satisfies <math>\nabla \times \vec{F}=\vec{0}</math>, it means it's not spinning around any axis, anywhere.  It makes sense to call such a field '''irrotational'''.
 
So, if a vector field satisfies <math>\nabla \times \vec{F}=\vec{0}</math>, it means it's not spinning around any axis, anywhere.  It makes sense to call such a field '''irrotational'''.
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{{MVCalc}}
 
{{MVCalc}}
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