Significance of E. Coli Evolution Experiments
Blount, Borland, and Lenski[1] claimed that a key evolutionary innovation was observed during a laboratory experiment. That claim is false. The claim was based on incorrect measurements of statistical significance. Rather than using a test from the statistics literature, a flawed test was contrived and used to measure significance. The flawed test (“mean mutation generation”) produced artificially low p-values.
Contents
Experiment One Data
The data from experiment one of the paper is shown below (see Table 1 of the paper). The expected outcomes under the null hypothesis (no evolutionary innovation occurs) are also shown.
| Generation | Trials | Mutants | Statics | Expected Mutants | Expected Statics |
|---|---|---|---|---|---|
| 0 | 6 | 0 | 6 | 0.333 | 5.667 |
| 10000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 20000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 25000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 27500 | 6 | 0 | 6 | 0.333 | 5.667 |
| 29000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 30000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 30500 | 6 | 1 | 5 | 0.333 | 5.667 |
| 31000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 31500 | 6 | 1 | 5 | 0.333 | 5.667 |
| 32000 | 6 | 0 | 6 | 0.333 | 5.667 |
| 32500 | 6 | 2 | 4 | 0.333 | 5.667 |
| Total | 72 | 4 | 68 | 4 | 68 |
When the flawed test is used to compute the significance of this data, the p-value is 0.0085 (see Table 2 of the paper). This p-value is considered statistically significant. However, when the data is analyzed using a standard method (the chi-square test) the p-value is 0.19. This p-value is much larger than the one from the paper and indicates that there is no reason to reject the null hypothesis. The chi-square test p-value for experiment two is small (0.0004). However, experiment three is not statistically significant because its p-value is 0.22.
The chi-square test is a common statistical method.[2] It can be implemented in Microsoft Excel. If the numbers from the last four columns of the experiment one data table (excluding the “totals” row) are entered into Excel in rows 1-12 and columns A-D, then the p-value can be computed by entering “=CHITEST(A1:B12,C1:D12)” into any empty cell of the spreadsheet.
Experiment Three Data
The experiment three data from Blount et al. is shown in the table below. The expected numbers of mutants under the null hypothesis (constant mutation rate) is also shown.
| Generation | Trials | Mutants | Statics | Expected Mutants | Expected Statics |
|---|---|---|---|---|---|
| 0 | 200 | 0 | 200 | 0.571 | 199.429 |
| 10000 | 200 | 0 | 200 | 0.571 | 199.429 |
| 20000 | 200 | 0 | 200 | 0.571 | 199.429 |
| 25000 | 200 | 0 | 200 | 0.571 | 199.429 |
| 27500 | 200 | 2 | 198 | 0.571 | 199.429 |
| 29000 | 200 | 0 | 200 | 0.571 | 199.429 |
| 30000 | 200 | 2 | 198 | 0.571 | 199.429 |
| 30500 | 200 | 0 | 200 | 0.571 | 199.429 |
| 31000 | 200 | 0 | 200 | 0.571 | 199.429 |
| 31500 | 200 | 0 | 200 | 0.571 | 199.429 |
| 32000 | 200 | 1 | 199 | 0.571 | 199.429 |
| 32500 | 200 | 1 | 199 | 0.571 | 199.429 |
| Total | 2800 | 8 | 2792 | 8 | 2792 |
Comparison of p-Values
The following table compares the p-values reported in Table 2 of Blount et al. to the chi-square p-values for the same experiments. For experiments one and three, the chi-square p-values are much larger than the "mean generation" test p-values from the paper.
| Experiment 1 | Experiment 2 | Experiment 3 | |
|---|---|---|---|
| p-Value from Paper | 0.0085 | 0.0007 | 0.082 |
| Chi-square p-value | 0.19 | 0.0004 | 0.22 |
References
- ↑ http://www.pnas.org/content/105/23/7899.full.pdf
- ↑ Mathematical Statistics with Applications by Wackerly, Mendenhall, and Scheaffer, Section 14.4.
See Also
http://www.sciencenews.org/index/feature/activity/view/id/40006/title/Molecular_Evolution
http://sciencenews.org/view/generic/id/40649/title/FOR_KIDS_Hitting_the_redo_button_on_evolution