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10 bytes added ,  03:47, November 24, 2012
→‎Lebesgue Integral: consistent use of mathbb
Line 105: Line 105:  
::<math>\chi_{\mathbb Q}(x) =
 
::<math>\chi_{\mathbb Q}(x) =
 
\begin{cases}
 
\begin{cases}
   1 & \mbox{if } x \in \mathbb Q, \\
+
   1 & \mbox{if } x \in \mathbb{Q}, \\
   0 & \mbox{if } x \notin Q
+
   0 & \mbox{if } x \notin \mathbb{Q}
 
\end{cases}</math>.
 
\end{cases}</math>.
 
Because the rationals are only countable, this function is zero "almost everywhere": there are far more irrationals than rationals, and the function is <math>0</math> at all of these.  Thus we would expect that  
 
Because the rationals are only countable, this function is zero "almost everywhere": there are far more irrationals than rationals, and the function is <math>0</math> at all of these.  Thus we would expect that  
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