::Please answer [[#A few questions for Aschlafly regarding the experiment of Cockcroft¹ and Walton]] and show us that you actually know what you are talking about.
::Please answer [[#A few questions for Aschlafly regarding the experiment of Cockcroft¹ and Walton]] and show us that you actually know what you are talking about.
::Thank you, --[[User:AugustO|AugustO]] 13:58, 10 January 2013 (EST)
::Thank you, --[[User:AugustO|AugustO]] 13:58, 10 January 2013 (EST)
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Neither the high school experiment, nor anything else about E=mc^2, purports to unify gravity and light. E=mc^2 does not relate to gravity; it would work in outer space. The "m" is ''inertial mass'', not gravitational mass. The correspondence between the two is incidental, and relates to Einstein's equivalence principle (a completely different phenomenon) and the Eotvos experiment.
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"Chemical reactions can yield a release of energy, but mass is neither created nor destroyed". Not so. It is a common misconception that E=mc^2 relates only to nuclear processes. It actually relates to all processes, though nuclear ones are the only ones for which the difference in mass can be reasonably measured. No one doubts the quantitative results, for nuclear processes, detailed on the article page. The equation E=mc^2, initially formulated on theoretical grounds, is in excellent agreement with those results. There is nothing about the theoretical underpinnings to suggest that there is some "threshold" below which Δm is zero, or that it only applies to certain types of interactions. There is good reason to believe that it applies everywhere, even though the mass difference, in the case of chemical reactions, is not readily measurable.
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By the way, another "table-top" demonstration of relativity may be found [http://www.physics.umd.edu/lecdem/outreach/QOTW/arch11/q218unipolar.pdf here]. It does not demonstrate E=mc^2; it's about electrodynamics under the Lorentz trasform.