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1,191 bytes added ,  02:43, January 20, 2013
→‎Nuclear Energy: final attempt
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::'''An neutron <math>{}^1_0n</math> has an atomic weight of 1.008664916 amu, a proton <math>{}^1_1p</math> has a mass of 1.007276466 amu, an electron has a mass of 0.000548580 amu. Therefore 92 protons, 92 electrons and 143 neutrons have a combined mass of 236.9589872 amu. But an atom of <math>{}^{235}_{92}U</math> - consisting of 92 protons, 92 electrons and 143 neutrons has a mass of 235.0439299. Does a liberal conspiracy hide roughly 1.915 amu of any atom of this isotope?
 
::'''An neutron <math>{}^1_0n</math> has an atomic weight of 1.008664916 amu, a proton <math>{}^1_1p</math> has a mass of 1.007276466 amu, an electron has a mass of 0.000548580 amu. Therefore 92 protons, 92 electrons and 143 neutrons have a combined mass of 236.9589872 amu. But an atom of <math>{}^{235}_{92}U</math> - consisting of 92 protons, 92 electrons and 143 neutrons has a mass of 235.0439299. Does a liberal conspiracy hide roughly 1.915 amu of any atom of this isotope?
 
:--[[User:AugustO|AugustO]] 16:14, 19 January 2013 (EST)
 
:--[[User:AugustO|AugustO]] 16:14, 19 January 2013 (EST)
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:::I will try one last time to explain this.  Suppose that blowing up an atomic bomb with 1 lb of Uranium releases x amount of energy, and blowing up an atomic bomb with 2 lbs of Uranium releases 2x amount of energy, and blowing up an atomic bomb with 3 lbs of Uranium releases 3x amount of energy. Could we then conclude that the energy released by the atomic bomb was proportional to its mass?  Is it possible that (for some liberal claptrap reason) we could define the metric system of energy units in a way that the proportionality constant was set equal to a number that equals the speed of light squared?  (If we invented a new unit of measuring energy "the Wschact" where one Wschact equaled the amount of energy released by converting one kg of uranium into energy), the equation would be: E (in Wschact units) = m (mass in kg)
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:::But because energy is measured in Joules, we have E =mc<sup>2</sup>, where c<sup>2</sup> converts between Wschacts and Joules.
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:::Any kid would agree that if you double the size of a bomb, the explosion would be twice as powerful.  So this is a very intuitive equation. I hope this helps. Thanks, [[User:Wschact|Wschact]] 21:43, 19 January 2013 (EST)
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