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No change in size ,  00:53, February 3, 2013
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:::The [[Cockcroft and Walton Experiment]] - as well as the experiments at the [http://web.mit.edu/newsoffice/2005/emc2.html MIT in 2005] - have shown that the [[Direct proportionality|constant of proportionality]] is c². And that's what all the mathematical derivations for special cases show, too: here is a neat trick for an engineer - develop mc² as a Taylor series (using the relativistic mass) and look closely at the first terms. That wouldn't work with c<sup><small>3/2</small></sup>  
 
:::The [[Cockcroft and Walton Experiment]] - as well as the experiments at the [http://web.mit.edu/newsoffice/2005/emc2.html MIT in 2005] - have shown that the [[Direct proportionality|constant of proportionality]] is c². And that's what all the mathematical derivations for special cases show, too: here is a neat trick for an engineer - develop mc² as a Taylor series (using the relativistic mass) and look closely at the first terms. That wouldn't work with c<sup><small>3/2</small></sup>  
 
:::BTW: You are always asking questions, awaiting answers - why are you not answering to [[#A few questions for Aschlafly regarding the experiment of Cockcroft¹ and Walton]]? --[[User:AugustO|AugustO]] 19:06, 2 February 2013 (EST)
 
:::BTW: You are always asking questions, awaiting answers - why are you not answering to [[#A few questions for Aschlafly regarding the experiment of Cockcroft¹ and Walton]]? --[[User:AugustO|AugustO]] 19:06, 2 February 2013 (EST)
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:::Andy, Isaac Newton would agree that the exponent would have to be 2 if it's anything.  F=ma.  Energy is defined as the force times distance, so the units of energy have to be mass times distance squared over time squared.  The exponent is fixed because of the definitions of energy and acceleration in classical Newtonian physics.  Of course this says nothing about the <i>magnitudes</i> of E, m or v but it does say any other exponent violates Newton's world. [[User:MelH|MelH]] 19:52, 2 February 2013 (EST)
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::Andy, Isaac Newton would agree that the exponent would have to be 2 if it's anything.  F=ma.  Energy is defined as the force times distance, so the units of energy have to be mass times distance squared over time squared.  The exponent is fixed because of the definitions of energy and acceleration in classical Newtonian physics.  Of course this says nothing about the <i>magnitudes</i> of E, m or v but it does say any other exponent violates Newton's world. [[User:MelH|MelH]] 19:52, 2 February 2013 (EST)
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