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→Arbitrary definition for using the imaginary square root of -1: I have to think about that further. Raising i to an exponential power seems to require an additional assumption.
*<math>e^{i\phi} = \cos \phi + i\sin \phi </math> follows quite straightforward by using <math>e^x = \sum_{n=0}^\infty \frac{x^n}{n!}</math>.
*<math>e^{i\phi} = \cos \phi + i\sin \phi </math> follows quite straightforward by using <math>e^x = \sum_{n=0}^\infty \frac{x^n}{n!}</math>.
--[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 14:32, 17 August 2015 (EDT)
--[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 14:32, 17 August 2015 (EDT)
:I have to think about that further. Raising <math>i</math> to an exponential power seems to require an additional assumption.--[[User:Aschlafly|Andy Schlafly]] ([[User talk:Aschlafly|talk]]) 14:36, 17 August 2015 (EDT)