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| | It is first taught using equations with "friendly" numbers in place of ''a'', ''b'', and ''c'' to get the student used to the process. | | It is first taught using equations with "friendly" numbers in place of ''a'', ''b'', and ''c'' to get the student used to the process. |
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| | + | :What one does is add and multiply by various carefully chosen constants to create an equation of the form: |
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| | + | :<math>d^2x^2 + 2dex + e^2 = f</math> where ''d'', ''e'' and ''f'' are constants expressed in ''a'', ''b'', and ''c''. |
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| | + | :This resolves to: |
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| | + | ::<math>(dx+e)^2 = f</math> (grouping) |
| | + | ::<math>dx + e = \pm \sqrt{f}</math> (take square root) |
| | + | ::<math>dx = -e \pm \sqrt{f}</math> (subtract e) |
| | + | ::<math>x = \frac{-e \pm \sqrt{f}}{d}</math> (divide by e) |
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| | By then applying the process to the general equation, we can derive the [[quadratic formula]]: | | By then applying the process to the general equation, we can derive the [[quadratic formula]]: |
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| − | <math>ax^2 + bx + c = 0</math> (given) | + | :<math>ax^2 + bx + c = 0</math> (given) |
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| − | <math>4a^2x^2 + 4abx + 4ac = 0</math> (multiply by 4a) | + | :<math>4a^2x^2 + 4abx + 4ac = 0</math> (multiply by 4a) |
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| − | <math>4a^2x^2 + 4abx = -4ac</math> (subtract 4ac) | + | :<math>4a^2x^2 + 4abx = -4ac</math> (subtract 4ac) |
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| − | <math>4a^2x^2 + 4abx + b^2 = -4ac + b^2</math> (add b^2) | + | :<math>4a^2x^2 + 4abx + b^2 = -4ac + b^2</math> (add b^2) |
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| − | <math>(2ax + b)^2 = b^2 - 4ac</math> (group each side) | + | :<math>(2ax + b)^2 = b^2 - 4ac</math> (group each side) |
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| − | <math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take sqaure root, allow for both roots) | + | :<math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take sqaure root, allow for both roots) |
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| − | <math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b) | + | :<math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b) |
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| − | <math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math> (divide by 2a) | + | :<math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math> (divide by 2a) |
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| | We can now determine the real or imaginary roots of any quadratic equation by simply inserting ''a'', ''b'', and ''c'' into the formula. | | We can now determine the real or imaginary roots of any quadratic equation by simply inserting ''a'', ''b'', and ''c'' into the formula. |