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495 bytes added ,  13:55, September 25, 2016
Added derivation
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The formula that depends on [[surface gravity]] is simpler:
 
The formula that depends on [[surface gravity]] is simpler:
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<math>v_{escape} = \sqrt{2gR}</math> where ''g'' = surface gravity.
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<math>v_{escape} = \sqrt{2gR}</math> where <math>g</math> is the [[acceleration]] due to gravity at the surface.
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===Derivation===
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Consider an object of mass <math>m</math> trying to escape from a [[planet]] of mass <math>M</math>. The energy required to do this is in the form of [[kinetic energy]], and is converted completely into gravitational potential energy. Hence:
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<math>\frac{1}{2} m v^2 = \int^{\infty}_{R} \frac{GMm}{r^2} dr</math>
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Performing the integration gives:
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<math>\frac{1}{2}  v^2 = \frac{GM}{R}</math>
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Rearranging gives the result above.
    
== See also ==
 
== See also ==
(username removed)

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