Changes
Jump to navigation
Jump to search
mLine 10:
Line 10:
− +
− +
− +
+
+
+
+
Inverse square law (view source)
Revision as of 15:55, September 25, 2016
, 15:55, September 25, 2016Formatting
|quote= }}</ref>
|quote= }}</ref>
Take a [[point source]] that is propagating something ([[light]], [[sound]], [[gravity]], [[electric field]], etc..) out.
Take a point source that is propagating something ([[light]], [[sound]], [[gravity]], [[electric field]], etc..) out.
The inverse square law can be derived by looking at the surface area of a [[sphere]] of radius ''r''. The surface area of a sphere is 4πr<sup>2</sup>. As the radius increases, the surface area of the sphere goes up with the square of the radius and the intensity of the phenomena will be inversely proportional to the [[surface area]].
The inverse square law can be derived by looking at the surface area of a [[sphere]] of radius <math>r</math>. The surface area of a sphere is <math>4 \pi r^2</math> As the radius increases, the surface area of the sphere goes up with the square of the radius and the intensity of the phenomena will be inversely proportional to the [[surface area]].
With gravity, the inverse square law can be seen in Gm<sub>1</sub>m<sub>2</sub> / r<sup>2</sup>.
With gravity, the inverse square law can be seen as:
<math>
F= \frac{Gm_1m_2}{r^2}
</math>
== Applications ==
== Applications ==
(username removed)