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1 byte removed ,  04:50, February 25, 2007
m
Fixed another typo.
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Likewise, if the kets are known, but a set of [[eigenvalues]] of the form:
 
Likewise, if the kets are known, but a set of [[eigenvalues]] of the form:
   −
<math>S=\left\lbrace\lambda_1,\lambda_2,\ldots,\lambda_n,\ldots,\right\rbrace</math>
+
<math>S=\left\lbrace\lambda_1,\lambda_2,\ldots,\lambda_n,\ldots\right\rbrace</math>
    
is also known, then a linear operator possessing those eigenvalues can be constructed.  The matrix representation for a linear operator <math>Q</math> with eigenvalues from <math>S</math>:
 
is also known, then a linear operator possessing those eigenvalues can be constructed.  The matrix representation for a linear operator <math>Q</math> with eigenvalues from <math>S</math>:
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