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1 byte removed ,  21:23, May 17, 2007
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                             p(B|A) = p(B)p(A|B)/p(A)
 
                             p(B|A) = p(B)p(A|B)/p(A)
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This is Bayes' theorem. The theorem is attributed to the Reverend [[Thomas Bayes]] (1702-19761) an English nonconformist minister, but it is likely to have been known to earlier mathematicians such as [[Pierre Laplace]].
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This is Bayes' theorem. The theorem is attributed to the Reverend [[Thomas Bayes]] (1702-1761) an English nonconformist minister, but it is likely to have been known to earlier mathematicians such as [[Pierre Laplace]].
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