| | ::::The book I'm reading (Charles Pinter's A Book of Abstract Algebra) seems to dodge the question - it has a section on inductive proofs, but it just starts with using integers and never mentions infinity. But the digits are countable, and go on for infinity, so they should be countably infinite - you should be able to match each digit to a digit in the countably infinite set of natural numbers, so that makes sense. | | ::::The book I'm reading (Charles Pinter's A Book of Abstract Algebra) seems to dodge the question - it has a section on inductive proofs, but it just starts with using integers and never mentions infinity. But the digits are countable, and go on for infinity, so they should be countably infinite - you should be able to match each digit to a digit in the countably infinite set of natural numbers, so that makes sense. |
| − | ::::I was trying to avoid the term "subset" as by axiom, a [[set]] can't contain itself. But I wasn't thinking of this as a set anyway, as there are no duplicates in a set, so the set of all digits in pi would just be the finite <--set <math>\{1, 2, 3, 4, 5, 6, 7, 8, 9, 0\}</math>--#> after removing duplicates.--[[User:AlChesapeake|AlChesapeake]] 20:22, September 4, 2021 (EDT) | + | ::::I was trying to avoid the term "subset" as by axiom, a [[set]] can't contain itself. But I wasn't thinking of this as a set anyway, as there are no duplicates in a set, so the set of all digits in pi would just be the finite {1,2,3,4,5,6,7,8,9,0} after removing duplicates.--[[User:AlChesapeake|AlChesapeake]] 20:22, September 4, 2021 (EDT) |