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: Please sign your entries using the signature button above.  Your math is flawed: many people do not identify themselves as either liberal or conservative.--[[User:Aschlafly|Aschlafly]] 21:56, 9 March 2007 (EST)
 
: Please sign your entries using the signature button above.  Your math is flawed: many people do not identify themselves as either liberal or conservative.--[[User:Aschlafly|Aschlafly]] 21:56, 9 March 2007 (EST)
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:: Fine then, let's group everyone into the categories liberal, conservative, and moderate. Let L1 be the fraction of liberal members of the public, L2 be the fraction of liberal members at Wikipedia, M1 be the fraction of moderate members of the public, M2 be the fraction of moderate members on Wikipedia, C1 be the fraction of conservatives in the public, and C2 be the fraction of conservatives on Wikipedia. By your own statistics, C1 = 2*L1, and 3*C2 = L2. Also, by definition, C1+L1+M1 = 1 and C2+L2+M2 = 1. Combining these equations, 2*L1+L1+M1 = 3L1 + M1 = 1, and L2+L2/3+M2 = (4/3)L2 + M2 = 1. Equating the two 1's, 3L1 + M1 = 1 = (4/3)L2 + M2. Shuffling things around, L2 = (3/4)*(3L1 + M1 - M2) = (9/4)L1 + (3/4)(M1-M2) = 2.25*L1 + 0.75*(M1-M2). L2/L1 = 2.25 + 0.75*(M1-M2)/L1 = 2.25 + 2.25*(M1-M2)/(1-M1) = 2.25*(1-M1+M1-M2)/(1-M1) = 2.25*(1-M2)/(1-M1). If the percentages of moderates in the public and Wikipedia are equal, then L2 = 2.25*L1, as I stated. If the number of moderates is higher in the public than on Wikipedia, then L2 is more than 2.25L1. If the number of moderates is lower in the public than on Wikipedia, then L2 is less than 2.25L1. What is the exact value? It depends on the explicit value of M1 and M2. You cannot say with any certainty that it is 6. In fact, it is most likely to be in the range from 2 to 2.5--[[User:Manchot|Manchot]] 22:27, 9 March 2007 (EST)
    
::Here is what the currently entry states at: [[Examples of Bias in Wikipedia]]   
 
::Here is what the currently entry states at: [[Examples of Bias in Wikipedia]]   
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