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Talk:Complete combustion reaction (view source)
Revision as of 23:33, July 21, 2007
, 23:33, July 21, 2007→Oxygen
:Why do you ''have'' to use O instead of the correct O<sub>2</sub>? A reaction between O and C<sub>x</sub>H<sub>y</sub> is ''not the same in any way'' as a reaction between O<sub>2</sub> and C<sub>x</sub>H<sub>y</sub>. I'm a 4th year chemical engineering student (plus I had 2 years of chemistry in high school) and I have never seen atomic oxygen written as O, unless we were discussing radical reactions. Also, on this article I had made other changes, but you reverted those along with my O<sub>2</sub>. Those were just clarity changes, I don't see why those had to be changed.
:Why do you ''have'' to use O instead of the correct O<sub>2</sub>? A reaction between O and C<sub>x</sub>H<sub>y</sub> is ''not the same in any way'' as a reaction between O<sub>2</sub> and C<sub>x</sub>H<sub>y</sub>. I'm a 4th year chemical engineering student (plus I had 2 years of chemistry in high school) and I have never seen atomic oxygen written as O, unless we were discussing radical reactions. Also, on this article I had made other changes, but you reverted those along with my O<sub>2</sub>. Those were just clarity changes, I don't see why those had to be changed.
:The only reason I explained this on your talk page is because you made the same mistake on two pages, and I thought it would be better to explain it once. [[User:Jazzman831|Jazzman831]] 15:27, 21 July 2007 (EDT)
:The only reason I explained this on your talk page is because you made the same mistake on two pages, and I thought it would be better to explain it once. [[User:Jazzman831|Jazzman831]] 15:27, 21 July 2007 (EDT)
::Rollback problems are fixed. You may explain in the article the diferences between O and O2. All of us will learn about it with your help.
::You may explain there: "A reaction between O and CxHy is not the same in any way as a reaction between O2 and CxHy"
::That is fine for me.
::But if you say oxygen you have to use "O". That do not change if it is in the middle of a reaction or not.
::Please answer me to my Talk page. Working in other matters, that is the best way for me. Thank you so much. --User:Joaquín Martínez, talk 19:31, 21 July 2007 (EDT)