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Line 7: Line 7:  
:<math>\mathbf{L_i}=\mathbf{L_f}</math>  
 
:<math>\mathbf{L_i}=\mathbf{L_f}</math>  
   −
:<math>\mathbf{m}\times{v}\times{l}= \mathbf{I}\times{\omega}</math>  
+
:<math>\mathbf{m}\times{v}\times{l}= \mathbf{I}\times{\omega}</math>
 +
 
 +
Thus
 +
 
 +
:<math>\mathbf{\omega}= \frac{\mathbf{m}\times{v}\times{l}}{\mathbf{I}}</math>
    
After the collision, there is conservation of energy such that the final potential energy of the rod (with the sticking block mass) equals the initial kinetic energy just after the collision:
 
After the collision, there is conservation of energy such that the final potential energy of the rod (with the sticking block mass) equals the initial kinetic energy just after the collision:
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