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Conservation of angular momentum (view source)

Revision as of 03:46, November 18, 2007

27 bytes added ,  03:46, November 18, 2007
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:<math>\mathbf{v^2}=2gh</math>
 
:<math>\mathbf{v^2}=2gh</math>
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 +
and thus the solution is:
    
:<math>\mathbf{cos\theta} = 1 - \frac{{6m^2}{h}}{l\times{(2m+M)(3m+M)}}</math>
 
:<math>\mathbf{cos\theta} = 1 - \frac{{6m^2}{h}}{l\times{(2m+M)(3m+M)}}</math>
    
[[category:physics]]
 
[[category:physics]]
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