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Conservation of angular momentum (view source)

Revision as of 03:53, November 18, 2007

1 byte removed ,  03:53, November 18, 2007
oops, correction
Line 48: Line 48:  
Thus the the moment of inertia ''I'' for a rod of length ''l'' and mass ''M'', with a small block of mass ''m'' at its end is simply this:
 
Thus the the moment of inertia ''I'' for a rod of length ''l'' and mass ''M'', with a small block of mass ''m'' at its end is simply this:
   −
:<math>\mathbf{I}= \frac{M}{3}\times{l^2} + 3m\times{l^2}</math>  
+
:<math>\mathbf{I}= \frac{M}{3}\times{l^2} + m\times{l^2}</math>  
    
which is:
 
which is:
Aschlafly
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