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Talk:Examples of Bias in Wikipedia (view source)
Revision as of 02:39, March 16, 2007
, 02:39, March 16, 2007reply
A bit more can be said when there are moderates '''if we accept as input data''' the assertion that WL/AL = 6 (it does not follow from the other input data). Then WL/AL = ((WL/(WC+WL+WM))/((AL/(AC+AL+AM)) = (2 + 1 + AM/AL)/(1/3 + 1 + WM/WL) = (3 + AM/AL)/(4/3 + WM/WL) = 6, the the lower bound on AM/AL is when WM = 0, so (3 + AM/AL)/(4/3) = 6, so 3 + AM/AL = 8, so AM/AL = 5. The data presented support the conclusion that there are at least 5 times as many moderate Americans as liberal Americans. [[User:Hdelbrook|Hdelbrook]] 22:21, 15 March 2007 (EDT)
A bit more can be said when there are moderates '''if we accept as input data''' the assertion that WL/AL = 6 (it does not follow from the other input data). Then WL/AL = ((WL/(WC+WL+WM))/((AL/(AC+AL+AM)) = (2 + 1 + AM/AL)/(1/3 + 1 + WM/WL) = (3 + AM/AL)/(4/3 + WM/WL) = 6, the the lower bound on AM/AL is when WM = 0, so (3 + AM/AL)/(4/3) = 6, so 3 + AM/AL = 8, so AM/AL = 5. The data presented support the conclusion that there are at least 5 times as many moderate Americans as liberal Americans. [[User:Hdelbrook|Hdelbrook]] 22:21, 15 March 2007 (EDT)
: Folks, what fractional reduction in liberals on Wikipedia would give it a balance comparable to the American public, which is 2:1 conservative? Answer: 1/6 reduction in Wikipedia liberals would be necessary. Ergo, Wikipedia is six times more liberal than the American public.
: But again, more interesting is why Wikipedians and yourselves won't simply admit your socially liberal views? Why conceal that?
: John Brown, did you revert your improper removal of information in the France entry???--[[User:Aschlafly|Aschlafly]] 22:39, 15 March 2007 (EDT)