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11 bytes added ,  11:39, May 21, 2008
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Consider the exponential of [[imaginary number]] <math>yi</math>,
 
Consider the exponential of [[imaginary number]] <math>yi</math>,
   −
<math>e^{yi}=1+yi+\frac{(yi)^2}{2!}+\frac{(yi)^3}{3!}+\frac{(yi)^4}{4!}+\frac{(yi)^5}{5!}+\ldots</math>,
+
<math>e^{yi}=1+yi+\frac{(yi)^2}{2!}+\frac{(yi)^3}{3!}+\frac{(yi)^4}{4!}+\frac{(yi)^5}{5!}+\ldots</math>
 +
:<math>=1+yi-\frac{y^2}{2!}-i\frac{y^{3}}{3!}+\frac{y^4}{4!}+i\frac{y^5}{5!}-\ldots</math>
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:as <math>i^{2}=-1</math>
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:<math>=(1-\frac{y^2}{2!}+\frac{y^4}{4!}-\ldots)+i(y-\frac{y^{3}}{3!}+\frac{y^5}{5!}-\ldots)</math>
   −
<math>e^{yi}=1+yi-\frac{y^2}{2!}-i\frac{y^{3}}{3!}+\frac{y^4}{4!}+i\frac{y^5}{5!}-\ldots</math>
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:<math>=(1-\frac{y^2}{2!}+\frac{y^4}{4!}-\ldots)+i(y-\frac{y^{3}}{3!}+\frac{y^5}{5!}-\ldots)</math>
   
:<math>=\cos y+i\sin y</math>
 
:<math>=\cos y+i\sin y</math>
   −
By the power laws then,
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By the power laws then all [[complex numbers] have an exponential,
    
<math>e^{x+yi}=e^{x}(\cos y+i\sin y)</math>.
 
<math>e^{x+yi}=e^{x}(\cos y+i\sin y)</math>.
    
[[category:mathematics]]
 
[[category:mathematics]]
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