Changes
Jump to navigation
Jump to search
← Older edit
Newer edit →
Taylor series
(view source)
Revision as of 11:39, May 21, 2008
11 bytes added
,
11:39, May 21, 2008
→Extensions of the Exponential Function
Line 16:
Line 16:
Consider the exponential of [[imaginary number]] <math>yi</math>,
Consider the exponential of [[imaginary number]] <math>yi</math>,
−
<math>e^{yi}=1+yi+\frac{(yi)^2}{2!}+\frac{(yi)^3}{3!}+\frac{(yi)^4}{4!}+\frac{(yi)^5}{5!}+\ldots</math>
,
+
<math>e^{yi}=1+yi+\frac{(yi)^2}{2!}+\frac{(yi)^3}{3!}+\frac{(yi)^4}{4!}+\frac{(yi)^5}{5!}+\ldots</math>
+
:<math>=1+yi-\frac{y^2}{2!}-i\frac{y^{3}}{3!}+\frac{y^4}{4!}+i\frac{y^5}{5!}-\ldots</math>
−
:
as
<math>i^{
2
}
=
-
1
</math>
+
:<math>
=(1-\frac{y^2}{2!}+\frac{y^4}{4!}-\ldots)+
i
(y-\frac{y^{3}}{3!}+\frac{y
^
5}
{
5!
}-
\ldots)
</math>
−
<math>e^{yi}=1+yi-\frac{y^2}{2!}-i\frac{y^{3}}{3!}+\frac{y^4}{4!}+i\frac{y^5}{5!}-\ldots</math>
−
:<math>=(1-\frac{y^2}{2!}+\frac{y^4}{4!}-\ldots)+i(y-\frac{y^{3}}{3!}+\frac{y^5}{5!}-\ldots)</math>
:<math>=\cos y+i\sin y</math>
:<math>=\cos y+i\sin y</math>
−
By the power laws then,
+
By the power laws then
all [[complex numbers] have an exponential
,
<math>e^{x+yi}=e^{x}(\cos y+i\sin y)</math>.
<math>e^{x+yi}=e^{x}(\cos y+i\sin y)</math>.
[[category:mathematics]]
[[category:mathematics]]
DanielB
346
edits
Navigation menu
Personal tools
Create account
Log in
Namespaces
Article
talk page
Variants
Views
Read
View source
View history
More
Search
Popular Links
Main Page
Recent changes
New Pages
Random page
Statistics
Edit Console
Special pages
Printable version