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:<big><math>\int\frac{2x}{x^2+3}dx=\int\frac{1}{u}du</math></big>
 
:<big><math>\int\frac{2x}{x^2+3}dx=\int\frac{1}{u}du</math></big>
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We can rewrite the intergal this way due to the subsitution of the x terms with the u terms.
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We can rewrite the integral this way due to the subsitution of the x terms with the u terms.
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Now we can solve the intergral in terms of u.
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Now we can solve the integral in terms of u.
    
:<big><math>\int\frac{1}{u}du=ln|u|+c</math></big>
 
:<big><math>\int\frac{1}{u}du=ln|u|+c</math></big>
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