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Talk:PNAS Response to Letter (view source)
Revision as of 22:00, September 22, 2008
, 22:00, September 22, 2008no edit summary
::::::Andy if you read Whitlock's paper you would see it say, and I quote, "Ideally each study is weighted proportional to the inverse of its error variance, that is, by the '''reciprocal of its squared standard error'''." It says nothing about weighting according to sample size, which is what you seem to be insisting should be done.
::::::Andy if you read Whitlock's paper you would see it say, and I quote, "Ideally each study is weighted proportional to the inverse of its error variance, that is, by the '''reciprocal of its squared standard error'''." It says nothing about weighting according to sample size, which is what you seem to be insisting should be done.
::::::Also Whitlock acknowledges in the paper that there is no preference for weighted versus equal weighting, so the fact that both equal weighting and weighting by the standard error give a statistically significant result shows that the 3 experiments combined support rejection of the null hypothesis. [[User:DanB|DanB]] 20:39, 21 September 2008 (EDT)
::::::Also Whitlock acknowledges in the paper that there is no preference for weighted versus equal weighting, so the fact that both equal weighting and weighting by the standard error give a statistically significant result shows that the 3 experiments combined support rejection of the null hypothesis. [[User:DanB|DanB]] 20:39, 21 September 2008 (EDT)
::::::ASchlafly, you state that I incorrectly apply "Whitlock's Z-transform" (actually the test belongs to Mosteller & Bush<ref>Mosteller, F. & Bush, R.R. 1954. Selected quantitative techniques. In: ''Handbook of Social Psychology,'' Vol. 1 (G. Lindzey, ed.)</ref> and/or Liptak<ref>Liptak, T. 1958. On the combination of independent tests. ''Magyar Tud. Akad. Mat. Kutato Int. Kozl.'' '''3''': 171-197</ref>). Whitlock describes weighting by the reciprocal of the squared standard error. The standard error of the mean is proportional to 1/sqrt(N), so the reciprocal of the squared standard error is proportional to N. Thus larger studies ''are'' given more weight. I maintain that the sample sizes N of the three replays are 4, 5, and 8 respectively. Rather than simply repeating that I am wrong, will you please state what ''you'' think the sample sizes of the three replay experiments are, and, in your opinion, what the ''correct'' application of the Z-transformation would be?--[[User:Brossa|Brossa]] 18:00, 22 September 2008 (EDT)
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