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20 bytes added ,  21:06, November 17, 2008
Bypass redirect so I don't have to later.
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Given two [[group]]s <math>G,G'</math>, a '''homomorphism''' from <math>G</math> to <math>G'</math> is a [[function]] <math>\phi : G \to G'\,</math> such that for all <math>a,b\in G</math>, <math>\phi (ab) = \phi (a) \phi (b) \,</math>
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Given two [[Group (mathematics)|group]]s <math>G,G'</math>, a '''homomorphism''' from <math>G</math> to <math>G'</math> is a [[function]] <math>\phi : G \to G'\,</math> such that for all <math>a,b\in G</math>, <math>\phi (ab) = \phi (a) \phi (b) \,</math>
    
<!--Apologies if the TeX and font size don't work well together.  I have Firefox set to use a specified font to avoid a weird bug, so I'm not sure how it'll look normally. - CSGuy -->
 
<!--Apologies if the TeX and font size don't work well together.  I have Firefox set to use a specified font to avoid a weird bug, so I'm not sure how it'll look normally. - CSGuy -->
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