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Talk:Axiom of Choice (view source)

Revision as of 00:17, November 28, 2008

727 bytes added ,  00:17, November 28, 2008
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::::I'll look into this further but upon first glance agree with Foxtrot.  Wikipedia, not here, is the place to pretend falsely that the Axiom of Choice cannot be questioned.  It is questioned, it is disfavored, and it does sometimes yield absurd results.  Further comments welcome here, and if anyone thinks someone was improperly blocked then let's look at ''all'' his edits here.--[[User:Aschlafly|Aschlafly]] 19:13, 27 November 2008 (EST)
 
::::I'll look into this further but upon first glance agree with Foxtrot.  Wikipedia, not here, is the place to pretend falsely that the Axiom of Choice cannot be questioned.  It is questioned, it is disfavored, and it does sometimes yield absurd results.  Further comments welcome here, and if anyone thinks someone was improperly blocked then let's look at ''all'' his edits here.--[[User:Aschlafly|Aschlafly]] 19:13, 27 November 2008 (EST)
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== Latest edit ==
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What's the point of this edit: to illustrate that another axiom also results in an absurdity?  It strikes me as wrong to try to justify the AOC by pointing out that an absurdity can be reached without using it also:
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:"Another seemingly absurd consequence of the Axiom of Choice is that there are subsets of the real line which do not have a well-defined Lebesgue measure. However, it is also possible to construct such a subset without using the Axiom of Choice.<ref>[http://matwbn.icm.edu.pl/ksiazki/fm/fm138/fm13812.pdf "The Hahn-Banach theorem implies the existence of a non-Lebesgue measurable set"]</ref>"
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--[[User:Aschlafly|Aschlafly]] 19:17, 27 November 2008 (EST)
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== References ==
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